No Limit: Find the limit of y/(sqrt(2)Abs(y)) when y->0

  • Thread starter scarebyte
  • Start date
  • Tags
    Limit
In summary, a limit is the value that a function approaches as the input approaches a certain value or point. To find the limit of a function, you can use algebraic techniques, properties of limits, or estimate using a graph or table of values. The limit of y/(sqrt(2)Abs(y)) when y->0 is 0 because as y approaches 0, the numerator gets smaller while the denominator gets larger, resulting in a quotient that approaches 0. This cannot be evaluated using direct substitution because the expression is undefined at the limit point.
  • #1
scarebyte
11
0

Homework Statement



find
limit y/(sqrt(2)Abs(y)) when y->0

Homework Equations





The Attempt at a Solution


limit y/sqrt(2)Abs(y)
if y > 0
limit =1/sqrt(2) when y->0
if y<0
limit=-1/sqrt(2) when y->0

so it has no limit?

thanks
 
Physics news on Phys.org
  • #2
Exactly. It has no limit.
 

1. What is the definition of a limit?

A limit is the value that a function approaches as the input approaches a certain value or point. It represents the behavior of the function near that point.

2. How do you find the limit of a function?

To find the limit of a function, you can either use algebraic techniques such as factoring and simplifying or use the properties of limits, such as the fact that the limit of a sum is the sum of the limits. You can also use a graph or a table of values to estimate the limit.

3. What is the limit of y/(sqrt(2)Abs(y)) when y->0?

The limit of y/(sqrt(2)Abs(y)) when y->0 is 0. This can be found by factoring out a y and rearranging the expression to get y * (1/(sqrt(2)Abs(y))). As y approaches 0, the term 1/(sqrt(2)Abs(y)) approaches infinity, but it is multiplied by a very small value of y, resulting in the limit being 0.

4. Why is the limit of y/(sqrt(2)Abs(y)) when y->0 equal to 0?

The limit of y/(sqrt(2)Abs(y)) when y->0 is equal to 0 because the expression is undefined at y=0, but as y gets closer and closer to 0, the value of the expression approaches 0. This is because the numerator (y) is getting smaller and smaller while the denominator (sqrt(2)Abs(y)) is getting larger and larger, resulting in a quotient that approaches 0.

5. Can the limit of y/(sqrt(2)Abs(y)) when y->0 be evaluated using direct substitution?

No, the limit of y/(sqrt(2)Abs(y)) when y->0 cannot be evaluated using direct substitution because the expression is undefined at y=0. Direct substitution only works when the expression is defined at the limit point.

Similar threads

  • Calculus and Beyond Homework Help
Replies
10
Views
827
  • Calculus and Beyond Homework Help
Replies
8
Views
801
  • Calculus and Beyond Homework Help
Replies
6
Views
759
  • Calculus and Beyond Homework Help
Replies
20
Views
459
  • Calculus and Beyond Homework Help
Replies
2
Views
511
  • Calculus and Beyond Homework Help
Replies
4
Views
690
  • Calculus and Beyond Homework Help
Replies
24
Views
2K
  • Calculus and Beyond Homework Help
Replies
20
Views
435
  • Calculus and Beyond Homework Help
Replies
10
Views
362
  • Calculus and Beyond Homework Help
Replies
1
Views
902
Back
Top