- #1
scarebyte
- 11
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Homework Statement
find
limit y/(sqrt(2)Abs(y)) when y->0
Homework Equations
The Attempt at a Solution
limit y/sqrt(2)Abs(y)
if y > 0
limit =1/sqrt(2) when y->0
if y<0
limit=-1/sqrt(2) when y->0
so it has no limit?
thanks
A limit is the value that a function approaches as the input approaches a certain value or point. It represents the behavior of the function near that point.
To find the limit of a function, you can either use algebraic techniques such as factoring and simplifying or use the properties of limits, such as the fact that the limit of a sum is the sum of the limits. You can also use a graph or a table of values to estimate the limit.
The limit of y/(sqrt(2)Abs(y)) when y->0 is 0. This can be found by factoring out a y and rearranging the expression to get y * (1/(sqrt(2)Abs(y))). As y approaches 0, the term 1/(sqrt(2)Abs(y)) approaches infinity, but it is multiplied by a very small value of y, resulting in the limit being 0.
The limit of y/(sqrt(2)Abs(y)) when y->0 is equal to 0 because the expression is undefined at y=0, but as y gets closer and closer to 0, the value of the expression approaches 0. This is because the numerator (y) is getting smaller and smaller while the denominator (sqrt(2)Abs(y)) is getting larger and larger, resulting in a quotient that approaches 0.
No, the limit of y/(sqrt(2)Abs(y)) when y->0 cannot be evaluated using direct substitution because the expression is undefined at y=0. Direct substitution only works when the expression is defined at the limit point.