- #1
BoldKnight399
- 79
- 0
lim as x approaches 4 from the right of [3(x-4)]^(x-4)
when you plug in 4 it becomes a 0^0. So I attempted to manipulate it so it would become a 0/0 form so I could l'hopital it. (sorry if I keep spelling it wrong)
so lim(x-4)ln(3x-12)=lny
then I l'hopitaled it:
lim (x-4)(1/3x-12)*3+ln(3x-12)=lny
lim 1+ln(3x-12)=lny
lim e + (3x-12)=y
so y=e
I do not know if my logic makes sense or not. If anyone sees any flaws in my logic, I would really like to know.
when you plug in 4 it becomes a 0^0. So I attempted to manipulate it so it would become a 0/0 form so I could l'hopital it. (sorry if I keep spelling it wrong)
so lim(x-4)ln(3x-12)=lny
then I l'hopitaled it:
lim (x-4)(1/3x-12)*3+ln(3x-12)=lny
lim 1+ln(3x-12)=lny
lim e + (3x-12)=y
so y=e
I do not know if my logic makes sense or not. If anyone sees any flaws in my logic, I would really like to know.