limit as h->0 when [cos(pi/2+h)]/h(adsbygoogle = window.adsbygoogle || []).push({});

when I sub in zero...I get 0/0...so I have to use L'hopital's rule

So I take the derivative of the numberator and denominator...

=[-sin(pi/2+h)*(0+1)]/1

=-sin(pi/2+h)

=-sin(pi/2+0)

= -1

is this correct?

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# Homework Help: Limit as h->0 when [cos(pi/2+h)]/h

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