- #1

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## Homework Statement

lim as x-> 0

(xcsc2x)/(cos5x)

## Homework Equations

lim as x-> 0 (sinx)/x = 1

## The Attempt at a Solution

(x(1/sin2x)) / (cos5x)

Not sure what I am supposed to do here! Thanks

:)

- Thread starter motorhead87
- Start date

- #1

- 1

- 0

lim as x-> 0

(xcsc2x)/(cos5x)

lim as x-> 0 (sinx)/x = 1

(x(1/sin2x)) / (cos5x)

Not sure what I am supposed to do here! Thanks

:)

- #2

Char. Limit

Gold Member

- 1,204

- 14

[tex]\lim_{x\rightarrow0} \frac{sin(x)}{x} = 1[/tex]

Then can you figure out what this limit is?

[tex]\lim_{x\rightarrow0} \frac{x}{sin(x)}[/tex]

And then if you use 2x instead of x, this limit should be just as easy:

[tex]\lim_{x\rightarrow0} \frac{2x}{sin(2x)}[/tex]

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