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Limit evaluation help

  1. Feb 16, 2005 #1
    lim as r->0 for sin(5r)/r
    I know that sinr/r=1 but with that 5r it's no use. So how do I take it into account for 5?
     
  2. jcsd
  3. Feb 16, 2005 #2
    Never mind
     
  4. Feb 16, 2005 #3

    dextercioby

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    I take it you saw that substitution...Good,then.Try to remember the method,it's useful in many cases.

    Daniel.
     
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