# Limit evaluation

1. Nov 27, 2005

### alephnought

Would anybody solve this problem for me?

I've tried it for a long time, but don't seem to get the answer.
I don't think I can apply L'Hospital's rule because the numerator is not zero or indeterminate while the denominator goes to zero

lim x-> -inf ((1+ e^(1/x))/e^x)

ok, if I assume the numerator is 1 - e^... and try to solve, I am not able to get rid of the e^x term

thanks

2. Nov 27, 2005

### HallsofIvy

Staff Emeritus
One of the very first things you should have learned about limits is that if the denominator of a fraction goes to 0 and the numerator does not, then the fraction does not have a limit!

3. Nov 27, 2005

I think the answer is $$+\infty$$ because a number divided by 0 tends to infinity.