# Limit of 1/x + 1/x^2 when x -> 3 from the left

1. Mar 14, 2005

### gillgill

Just want to check my answers...

1) lim (1/x) + (1/x^2)
x-> 3-
ans=0

2) lim √(x^2+4)-2/x
x->0
ans=0

3) lim (√(2x^2+5) -x)
x-> positive infinity
ans= positive infinity

2. Mar 14, 2005

### Data

1) and 2) are wrong.

3) is right.

First let's check that I understand your questions right. Are these the limits you're trying to find?

$$\lim_{x\rightarrow 3^-} \left(\frac{1}{x} + \frac{1}{x^2}\right)$$

$$\lim_{x \rightarrow 0} \left( \sqrt{x^2 + 4} - \frac{2}{x}\right)$$

$$\lim_{x \rightarrow \infty} \left( \sqrt{2x^2 + 5} - x \right)$$

If so, why don't you show us the work you did for the first two.

3. Mar 14, 2005

### gillgill

the second one is √(x^2+4)-2 all over x
how about you tell me the correct answer...and i'll try to find my mistake?

4. Mar 14, 2005

### HallsofIvy

Staff Emeritus