# Limit of a Reimann Sum

1. Nov 11, 2013

### Qube

1. The problem statement, all variables and given/known data

2. Relevant equations

delta x = (b-a)/n

3. The attempt at a solution

Well, from the delta x formula I can figure out the limits of integration. They're 4 and 0. That leaves us with three possible answer choices. I'm suspecting that the 4i/n term goes away and the answer is B, but I really don't know and I'm not even sure where to begin.

2. Nov 11, 2013

### Staff: Mentor

You have the interval [0, 4] that you will divide into n subintervals of equal length. How would you write xi, the x value in the i-th subinterval? The x value could be at the left or right end of a given subinterval, or somewhere in the middle of it.

3. Nov 11, 2013

### Qube

I'm not sure what terms to write xi in terms of. I guess, (x/n) would give me the width of each subinterval and I'm not sure what else.

4. Nov 11, 2013

### Staff: Mentor

No, the width of each subinterval would be 4/n. Since the summation has cos(2 + ...), that's going to show up in the integral as well.

5. Nov 12, 2013

### Qube

So the integral would have cos (2+x) as the integrand?

6. Nov 12, 2013

### Staff: Mentor

Yes. Do you see how it works? Since i is running from 1 to n, 4i/n represents the x value at the right side of each subinterval, and cos(2 + 4i/n) is the function value associated with that x value.

7. Nov 12, 2013

### Qube

Alright, I see :)! 4/n is the width of each sub interval. The i represents each sub interval.