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Forums
Mathematics
Calculus
Limit of a Sequence (Updated with progress)
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[QUOTE="slwarrior64, post: 6785191, member: 721439"] [ATTACH type="full"]312016._xfImport[/ATTACH] Hello, I know I posted this question recently but I wanted to update with my progress. I have figured out what the limit should be but I would really appreciate help with how to use the definition of the limit of a sequence to prove it! What I have is:Suppose n is extremely large, then both n^2+1 and n^2 have almost the same size. Similarly both n and n+1 have almost the same size. Therefore, as n grows larger and larger, we can replace the numerator by sqrt (n^2)=n and the denominator by n. Therefore the guess value for the limit should be 1 since the numerator and denominator should cancel. I am pretty sure this is right, but I am not sure how to answer it in the way this question is asking. [/QUOTE]
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Forums
Mathematics
Calculus
Limit of a Sequence (Updated with progress)
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