With the equation [tex]\frac{(-1)^{x+1}}{2\cdot2^{x - 1}}[/tex] can I just use the argument that 2^(x-1) will reach infinity faster than (-1)^(n+ 1) so the limit as x -> inf is 0? Because I don't see what I can do the equation to make it more "obvious".(adsbygoogle = window.adsbygoogle || []).push({});

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# Homework Help: Limit of a series

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