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Here, it says that for the limit f(x) = |x| / x,

|x| = { x, x > 0

-x, x < 0 }

What I don't undestand is why is |x| = -x for values under zero? Isn't the absolute value for negative values just x and not -x?

thanks.

EDIT: I don't want to start a new thread, but I got stuck on this next question :(

Lim x approaching -1 of

3(1-x^2) / x^3 + 1

I tried multiply the equation by x^3 - 1 / x^3 - 1

and I ended up with 0 / -2.

The answer is however 2... any help would be helpful;!

Thanks

|x| = { x, x > 0

-x, x < 0 }

What I don't undestand is why is |x| = -x for values under zero? Isn't the absolute value for negative values just x and not -x?

thanks.

EDIT: I don't want to start a new thread, but I got stuck on this next question :(

Lim x approaching -1 of

3(1-x^2) / x^3 + 1

I tried multiply the equation by x^3 - 1 / x^3 - 1

and I ended up with 0 / -2.

The answer is however 2... any help would be helpful;!

Thanks

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