What is the Limit of (E^x+1)^1/x as x Approaches Infinity?

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In summary, the limit of (E^x+1)^1/x as x approaches infinity is equal to e, the base of the natural logarithm. It is not equal to zero and can be evaluated without using L'Hopital's rule. However, as x approaches negative infinity, the limit does not exist. The limit can also be evaluated for non-integer values of x, as long as x is a real number.
  • #1
SteveBell
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Homework Statement



Lim (E^x-1)^(1/x)
x->Infinito

L'Hospital?

Homework Equations



Lim (1+1/x)^x=E
x->Infinito

The Attempt at a Solution



Help!
 
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  • #2
If you want to use l'Hopital you will have to take the logarithm of the limit first. Remember [itex]e^{\ln x} =x[/itex] and don't forget to show us your work!
 
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  • #3
Thank you very much for your advice.

I'm still unsure how to approach this one. Apply Ln() to the entire limit?
 
  • #4
Yes write the limit as [itex]\exp(\ln[(e^x-1)^{(1/x)}])[/itex].
 

1. What is the limit of (E^x+1)^1/x as x approaches infinity?

The limit of (E^x+1)^1/x as x approaches infinity is equal to e, the base of the natural logarithm. This can be mathematically proven using L'Hopital's rule or by recognizing that the expression approaches e^1, which is equal to e.

2. Is the limit of (E^x+1)^1/x equal to zero?

No, the limit of (E^x+1)^1/x is not equal to zero. As x approaches infinity, the expression approaches e, which is a non-zero value. This can also be seen by plugging in larger and larger values for x, which will result in a larger and larger value for the expression.

3. Can the limit of (E^x+1)^1/x be evaluated without using L'Hopital's rule?

Yes, the limit of (E^x+1)^1/x can be evaluated without using L'Hopital's rule. As x approaches infinity, the expression approaches e, which can be determined by recognizing the pattern and properties of exponential functions.

4. What happens to the limit of (E^x+1)^1/x as x approaches negative infinity?

As x approaches negative infinity, the limit of (E^x+1)^1/x does not exist. This is because the expression will approach e for positive values of x, but will approach 0 for negative values of x. Therefore, the limit is undefined at negative infinity.

5. Can the limit of (E^x+1)^1/x be evaluated for non-integer values of x?

Yes, the limit of (E^x+1)^1/x can be evaluated for non-integer values of x. As long as x is a real number, the limit will still approach e as x approaches infinity. This can be seen by plugging in decimal values for x and observing that the expression approaches e.

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