- #1

- 1,039

- 2

## Homework Statement

[itex]lim_{x \to 0+} ln(sin(x))[/itex]

[itex]lim_{x \to \infty} [ln(1+x^2)-ln(1+x)][/itex]

## Homework Equations

## The Attempt at a Solution

I'm really not sure how to take this limit at all?

I know (from using a table) that it tends towards -infinity, but I am not sure how to go about taking it manually?

I am thinking that because as x approaches 0, sin(x) approaches 0, you can treat sin(x) like x. Then as x approaches 0, ln(x) approaches -infinity.

For the second one, if I separate it into two limits, they both go towards infinity, then it's infinity - infinity?

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