[tex]a_n = 2^n/(3^n + 1)[/tex](adsbygoogle = window.adsbygoogle || []).push({});

Find the limit as n -> infinity

So I separated the fraction into [tex] (1/3)(2/3)^n [/tex]

Then limit = 1/3 [tex] lim_(n->infinity) (2/3)^n. [/tex]

So, my question is, how do you find the limit [tex] (2/3)^n. [/tex] Is analysis of functions simply enough, i.e. looking at how fast they increase?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Limit of Sequence

**Physics Forums | Science Articles, Homework Help, Discussion**