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Limit problem solution

  • Thread starter icosane
  • Start date
1. Homework Statement

lim as x goes to 0 of

[x*csc(2x)] / cos(5x)


3. The Attempt at a Solution

The book solution says the answer is 1/2. I keep getting zero as an answer because of the x in the numerator and am unsure of how else to go about the problem. I'm pretty sure I'm supposed to use the limit as x goes to 0 of sinx / x, but even when I get to that point the limit of x as x goes to 0 always gives me an answer of zero. What am I doing wrong? Thanks!
 
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The part to be concerned with is x*csc(2x), since the limit of cos(5x) is 1, as x goes to 0. If you can establish a limit for x*csc(2x), then lim x*csc(2x)/cos(5x) will be = lim x*csc(2x).

x*csc(2x) = x/sin(2x), so all you need now is 2x in the numerator instead of the x that is there. Can you turn x into 2x by multiplying by 1 in some form?
 

lanedance

Homework Helper
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2
so you have

[tex] \frac{x.csc(2x)}{cos(5x)} = \frac{x.}{sin(2x).cos(5x)}[/tex]

so the denmoinator goes to zero as well, so you can't say it is zero...
 
So the lim as x goes to 0 of x/sin(x) is also equal to 1? I assume that is the case because multiplying by 2/2 gives the solution of 1/2. Thanks a lot, I really appreciate it.

Just out of curiosity now, is the lim as x goes to 0 of x/(1-cos(x)) = infinity?
 

lanedance

Homework Helper
3,304
2
lim as x goes to 0 sin(x)/x is one, as is sin(x)/x

think about this, if
[tex]\stackrel{lim}{x \rightarrow 0} f(x) = c [/tex]

then what is
[tex]\stackrel{lim}{x \rightarrow 0} \frac{1}{f(x)} = ? [/tex]

the second limit is true
[tex]\stackrel{lim}{x \rightarrow 0} \frac{x}{(1-cos(x))} = \infty [/tex]
can you show why?

(l'hopitals rule is good for all of these if you know it...)
 
32,580
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So the lim as x goes to 0 of x/sin(x) is also equal to 1? I assume that is the case because multiplying by 2/2 gives the solution of 1/2. Thanks a lot, I really appreciate it.

Just out of curiosity now, is the lim as x goes to 0 of x/(1-cos(x)) = infinity?
No, the limit doesn't exist.
[tex]\lim_{x \rightarrow 0^+} x/(1 -cos(x)) = \infty[/tex]
while

[tex]\lim_{x \rightarrow 0^-} x/(1 -cos(x)) = -\infty[/tex]
 

lanedance

Homework Helper
3,304
2
good pickup - my mistake
 

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