Hello. I have been trying to find this limit: Lim as x --> 1 of (sin((1-x)/2)*tan(Pi*x/2)) Of course I dont want to solve it using L'Hospital. I have tried several ways but ended up in one of these. lim as y -->0 of (y*tan(pi/2-y*pi)) The answer when using L'Hospital is 1/pi. How can I go about getting the same answer without using L'Hospital. Thanks.