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I have been trying to find this limit:

Lim as x --> 1 of (sin((1-x)/2)*tan(Pi*x/2))

Of course I dont want to solve it using L'Hospital. I have tried several ways but ended up in one of these.

lim as y -->0 of (y*tan(pi/2-y*pi))

The answer when using L'Hospital is 1/pi.

How can I go about getting the same answer without using L'Hospital. Thanks.

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# Limit problem

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