- #1

- 65

- 2

## Homework Statement

Find [tex]lim_{x->- \infty} \; \frac{(x^6+8)^{1/3}}{4x^2+(3x^4+1)^{1/2}}[/tex]

## Homework Equations

N/A

## The Attempt at a Solution

Factoring out [tex]\frac {(-x^6)^{1/3}}{-x^2}[/tex] leaves me with [tex]\frac{(-1-8x^{-6})}{-4+(3+x^{-4})^{1/2

}}[/tex] Taking the limit at infinity gives me [tex]\frac{-1}{-4+3^{1/2}}[/tex], which is wrong.