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Find the Limit:

lim log10 (x2-5x+6)

x->3+

- Thread starter shorti2406
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- 12

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Find the Limit:

lim log10 (x2-5x+6)

x->3+

- 28

- 0

x->3+

Put x = 3+h, where h>0 and limit of h as zero solving, we have

lim log (h2+h) = lim logh + lim log(h+1) = lim log h = (-infinity)

h->0 h->0 h>0 h->0

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