# Limit question...

1. ### Miike012

Problem:

Lim sin(cos(x))/sec(x)
x -> 0

The answer in the book is sin(1).. which is obvious... but why do I not arrive at the same answer doing is this way.....

Knowing as x approaches zero, sin(x)/x approaches 1....

( Sin(cos(x))/cos(x) )(cos^2(x)) = (1)(1) = 1 = / = sin(1)...???

2. ### gb7nash

805
The bolded part is correct. However, what is cos(x) approaching as x approaches 0?

3. ### Miike012

cos(x) approaches 1..

4. ### gb7nash

805
Ok, so since cos(x) goes to 1:

$$\lim_{x \to 0} \frac{\sin(\cos(x))}{\cos(x)}$$

is equivalent to:

$$\lim_{u \to 1} \frac{\sin(u)}{u}$$

We can't apply the sin(_)/_ rule here. The term inside of the sine approaches 1.

Thank you.

6. ### Miike012

I wasn't aware that you can't use that rule if the function actually approaches a value.

7. ### gb7nash

805
$$\lim_{x \to 0}\frac{\sin(x)}{x} = 1$$

x needs to approach 0. If it approaches any other value (or does not exist), you can't use this identity.

8. ### Miike012

that makes sense. Thank you.