# Limit question

This isn't really homework for a class, but i figured this would be the most appropriate place for this question:
What would this quantity be?
$$\lim_{t \rightarrow \infty} e^{-i \alpha |x - t|} \cdot (|x -t| - 1) - \lim_{t \rightarrow - \infty} e^{-i \alpha |x - t|} \cdot (|x -t| - 1) = ?$$

It looks to me like it is just zero, but I was hoping it would be:
$$\frac{2e^{-i \alpha x}}{1 + \alpha^2}$$

where $$\alpha$$ is a real number, since this was the last step in proving that
$$f(t) = e^{-i \alpha t}$$

is an eigenfunction of the kernel:
$$K(x,t) = e^{-i \alpha |x - t|}$$

with an eigenvalue:
$$\lambda = \frac{2}{1 + \alpha^2}$$

Perhaps I solved my integral wrong or made a mistake somewhere.

AKG
Homework Helper
The quantity looks to be undefined. It looks to be of the form Y - Z, where Y and Z are themselves undefined, so clearly their difference is undefined. Each of the limits are themselves undefined because they are the limits of products of two functions, one of which is period, the other which goes to infinity.

Well, here's how I got there anyway:
$$\hat{K} |f \rangle = \lambda |f \rangle$$

Then I projected into position space:
$$\langle x| \hat{K} |f \rangle = \lambda \langle x|f \rangle$$

Threw in an identity operator:
$$\langle x| \hat{K} (\int^{\infty}_{- \infty} dt |t \rangle \langle t|)|f \rangle = \lambda \langle x|f \rangle$$

Which simplifies to:
$$\int^{\infty}_{- \infty} dt \cdot K(x,t) \cdot f(t) = \lambda \cdot f(x)$$

So then I just plugged in:
$$\int^{\infty}_{- \infty} dt \cdot e^{-|x - t|} \cdot e^{-i \alpha t} = \frac{2e^{-i \alpha x}}{1 + \alpha^2}$$

This leaves me with the problem of trying to find that integral, namely:
$$\int^{\infty}_{- \infty} dt \cdot e^{-|x - t|} \cdot e^{-i \alpha t}$$

I put this into Integrals.com and got this back:
$$\frac{|x -t| e^{-i (|x -t| + \alpha t)}}{(x - t)} |^{\infty}_{- \infty}$$

That's where the limit came from anyway.

Oh whoops, forgot to put this into the function above:
$$|x - t|$$

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Galileo
$$\int^{\infty}_{0} dt \frac{t \sin{xt}}{a^{2} + t^{2}}$$