- #1
gabel
- 17
- 0
Is the following true, if no is there som theory i can studdy?
##\lim_{\Delta x \to 0}f(x+\Delta x) \cdot \Delta x = 0##
##\lim_{\Delta x \to 0}f(x+\Delta x) \cdot \Delta x = 0##
gabel said:Is the following true, if no is there som theory i can studdy?
##\lim_{\Delta x \to 0}f(x+\Delta x) \cdot \Delta x = 0##
Who told you that? gopher_p, in the only other response here, said "this is not always true".gabel said:I was told in general, so there must be some functions that does the oppeist?
The notation represents the concept of a limit in calculus. It is read as "the limit of f(x) times delta x as delta x approaches 0 is equal to 0". This notation is used to express the idea of a variable approaching a certain value as it gets infinitely close to that value.
This limit is evaluated using mathematical techniques such as substitution, factoring, or algebraic manipulation. It may also require the use of calculus techniques such as L'Hopital's rule or the squeeze theorem.
In order for this limit to be true, the function f(x) must be continuous and differentiable at the point x. Additionally, the limit must exist and be finite.
No, this limit may not be true for all values of x and delta x. It depends on the specific function f(x) and the value of x and delta x being considered. It is possible for this limit to be true for one set of values but not for another.
This limit plays a crucial role in calculus and is used to define important concepts such as derivatives and integrals. It also has applications in physics, engineering, and other scientific fields where the concept of a variable approaching a certain value is important.