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Limit to derivative proof

  1. Jun 5, 2012 #1
    Suppose I have

    limt[itex]\rightarrow∞[/itex] f(g(t)) = 0


    limt[itex]\rightarrow-∞[/itex] f(g(t)) = 0

    How would I prove [itex]\frac{df}{dt}[/itex][itex]_{|}\Re[/itex] = 0? (over the reals)
    Last edited: Jun 5, 2012
  2. jcsd
  3. Jun 5, 2012 #2
    This question doesn't make sense. Could you provide some context?
  4. Jun 6, 2012 #3
    I'm having problems displaying what I want to convey. Basically I proved that the limit for the curvature function will always converge to zero for any real continuous function and now I want to prove that the derivative with respect to time will always converge to zero.

    So, essentially I need to prove that the integral over the reals of the curvature function will always converge to some constant.
  5. Jun 6, 2012 #4
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