(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

limit as x-> -oo of x+(x^2+3)^(1/2) (square root)

2. Relevant equations

n/a

3. The attempt at a solution

i first multiplied the top and bottom (which is just 1) by the conjugate to get:

-3

--------------

[x - (x^2+3)^(1/2)]

then i divided by x on top and bottom to get:

-3/x

-----------

[x/x - (1 + 3/x2)^(1/2)]

but now what do i do? the top goes to 0 but the bottom also goes to 0 (because its 1 - (1+0)^(1/2)). but the answer is suppose to be 0.

0/0 isnt 0. can someone point me in the right direction? thanks.

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# Homework Help: Limit to negative infinity

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