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**1. Homework Statement**

limit as x-> -oo of x+(x^2+3)^(1/2) (square root)

**2. Homework Equations**

n/a

**3. The Attempt at a Solution**

i first multiplied the top and bottom (which is just 1) by the conjugate to get:

-3

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[x - (x^2+3)^(1/2)]

then i divided by x on top and bottom to get:

-3/x

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[x/x - (1 + 3/x2)^(1/2)]

but now what do i do? the top goes to 0 but the bottom also goes to 0 (because its 1 - (1+0)^(1/2)). but the answer is suppose to be 0.

0/0 isnt 0. can someone point me in the right direction? thanks.