1. The problem statement, all variables and given/known data Find the limit as x -> 0+ of (sin x)(ln x) 2. Relevant equations None 3. The attempt at a solution I rewrote this as (sin x) / (1/ln x), then using L'Hopital it becomes: (cos x) / [(-ln x) / (ln x)2] = [(ln x)2 cos x] / (-ln x) So I get limit as x -> 0+ of [(ln x)2 cos x] / (-ln x) Which isn't any better. I'm not sure if I can even use L'Hopital here because it requires that substitution gives the indeterminate state, but I don't know if 0+/0+ really counts. Any thoughts?