- #1

phil ess

- 70

- 0

## Homework Statement

Find the limit as x -> 0

^{+}of (sin x)(ln x)

## Homework Equations

None

## The Attempt at a Solution

I rewrote this as (sin x) / (1/ln x), then using L'Hopital it becomes:

(cos x) / [(-ln x) / (ln x)

^{2}] = [(ln x)

^{2}cos x] / (-ln x)

So I get limit as x -> 0

^{+}of [(ln x)

^{2}cos x] / (-ln x)

Which isn't any better. I'm not sure if I can even use L'Hopital here because it requires that substitution gives the indeterminate state, but I don't know if 0

^{+}/0

^{+}really counts. Any thoughts?