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Limit with a constant

  1. Oct 2, 2007 #1
    1. The problem statement, all variables and given/known data

    Find in terms of the constant a

    Lim h --- > 0

    8 (a+h)² - 8a²

    3. The attempt at a solution

    I have no idea how to even approach it so some pointers would be nice.
    It hasn't been long since I started calculus. I am not sure weather we covered this
    or not , classes are so heavy with content and passes quickly :s .

    anyways what I am sure we have seen until now is

    - squeeze
    - Limit laws

    we have seen some things concerning continuity theorems altho am currently lost in them.
  2. jcsd
  3. Oct 3, 2007 #2
    Well,if you substitute in the value of h=0 directly, then you will get 0/h = 0.
    So, why don't you try to expand the numerator? Then, proceed to the operations and eventually, the h at the denominator will be cancelled out.
  4. Oct 3, 2007 #3
    well I end up with 16a = something . am giong to look at it more
    Last edited: Oct 3, 2007
  5. Oct 3, 2007 #4
    huh.. well the answer Is 16a altho I don't really understand it.
  6. Oct 3, 2007 #5
    Ooo I get it now well thanks for your time.
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