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## Homework Statement

lim as x approaches 0 of (x + 1)

^{ln x}

## Homework Equations

## The Attempt at a Solution

I tried using ln y = (ln x)[ln (x + 1)]

then:

ln (x + 1)

----------

1

---

ln x

to make it eligible for L'Hopital's Rule. Then differentiating the numerator and the denominator, I got:----------

1

---

ln x

1

---

x + 1

-------

-1

---------

x(ln x)

Then I brought the denominator of the denominator up:---

x + 1

-------

-1

---------

x(ln x)

^{2}

-x(ln x)

----------

x + 1

^{2}----------

x + 1

The answer is supposed to be 1. Therefore my differentiating should have evaluated to 0. Doesn't my answer give -infinity? Please help. I suck at ln and e. I must have missed something.

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