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Limiting Reactant Problem

  1. Oct 18, 2009 #1
    1. The problem statement, all variables and given/known data
    Sodium hydroxide reacts with carbon dioxide as follows,
    2 NaOH (s) + CO2 (g) [tex]\rightarrow[/tex] Na2CO3 (s) + H2O (g) ​

    Suppose 400. g of NaOH (s) is allowed to react with 308. g of CO2 (g)

    A. What is the limiting reactant? (Answer: NaOH)
    B. What mass of sodium carbonate can be produced? (Answer: 530g)
    C. What mass of excess reactant remains after the limiting reactant has been consumed? (Answer: 88g of CO2 remains)


    2. Relevant equations

    N/A


    3. The attempt at a solution

    PART A

    NaOH = 47. g/mol
    CO2 = 42. g/mol

    (400. g) / (2 * 47. g/mol) = 4.3 mol NaOH
    (308. g) / (42. g/mol) = 7.3 mol CO2

    Limiting Reactant: NaOH

    PART B

    Sodium carbonate (Na2CO3) = 120 g/mol

    (120 g/mol Na2CO3/1 mol Na2CO3)(1 mol Na2CO3 / 2 mol NaOH)(1 mol NaOH / 47. g/mol NaOH)(400 g NaOH) = 425 g Na2CO3
     
  2. jcsd
  3. Oct 18, 2009 #2

    Borek

    User Avatar

    Staff: Mentor

    No & no.

    --
     
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