2Al+3Cl2=Al2Cl6 a)which reactant is limiting if 2.70g Al and 4.05g Cl3 is mixed. b)what mass of Al2Cl3 can be produced. for part a i found the limiting reactant to be Cl2. I dont understand what im supposed to do for the second part. Should i write another equation as Al2Cl3 as the product, Al, and Cl2 as the reactants, balance it, and then use the limiting reagant from the aboove part to find the mass of Al2Cl3? Im not really sure what the question is trying to ask.