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Let d and K be given real numbers. Suppose that lim f(x) > K.

x->c

Show that there is a number h>0 such that f(x) > K for all x in the punctured open interval of width 2h centred at d.

The only hint that i was given was that if there are two real numbers as close as you like, then they are basically the same real.

How can i show this using this idea?