- #1
fstam2
- 10
- 0
Hey there, I need a little push in the right direction.
Here is the question:
The slope of the tangent line to the graph of the exponential function
y=2^x at the point (0,1) is lim x approaches 0 (2^x-1)/x.
Estimate the slope to three decimal places.
Where I am getting confused is which formula do I plug (x) into to find a secant slope?
I hope I asked the right question.
Thanks
Here is the question:
The slope of the tangent line to the graph of the exponential function
y=2^x at the point (0,1) is lim x approaches 0 (2^x-1)/x.
Estimate the slope to three decimal places.
Where I am getting confused is which formula do I plug (x) into to find a secant slope?
I hope I asked the right question.
Thanks