Please help, i take out n^2 top and bottom so end up with 0 as demominator.... Find lim (n to infinity) xn xn = (n^2 + log n)/(2n^3 - 1)^(1/2) ...?
[tex]\lim_{n\to \infty} x_n = \lim_{n\to\infty} \left( \frac{ 1+ \frac{\log n}{n^2} }{ \sqrt{ \frac{2n^3-1}{n^4}}} \right)[/tex] Consider separately, what is the numerator tending towards? How about the denominator?