OK I probably have some dumb questions here but it might be partially due to the lack of examples at my disposal and minimal explanation in my text.(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \lim_{x\to{0}}(x+1)^{3} = 1 [/tex]

[tex]\mid f(x) - L \mid < \epsilon [/tex]

[tex]\mid(x+1)^{3} - 1\mid < \epsilon [/tex]

now I know that delta is as follows:

[tex] 0 < \mid x - a\mid < \delta [/tex]

[tex]0 < \mid x - 0 \mid < \delta [/tex]

as far as i know that i need to pick delta = min{1, ??}. I know that you pick 1 for convention but from my example i' am little stumped on how to get the other delta choice. If anyone knows of some other links to examples of these types of problems please send them along.

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# Limits at a real number, using epsilon and delta

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