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Limits of a Trigonometric Function

  1. Oct 9, 2005 #1

    lim(x->0) for (tanx - sinx) / (sinx)^2

    This is what I got:

    = (sinx-sinxcosx) / (cosx)(sinx)^2
    = (sinx)(1-cosx) / (sinx)(sinx)(cosx)
    = (1 - cosx) / (sinx)(cosx)

    However, I can't figure out what to do from this step, as the limit still equals 0/0 at this stage.
  2. jcsd
  3. Oct 9, 2005 #2


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    Why are we posting twice -_-
  4. Oct 9, 2005 #3
    More people in this forum....
  5. Oct 10, 2005 #4


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  6. Oct 11, 2005 #5


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    You might see if you can use this handy trig fact:

    [tex] (1 + \cos(x))(1-\cos(x)) = 1-\cos^2(x) = \sin^2(x)[/tex]

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