Limits of a Trigonometric Function

  • Thread starter dekoi
  • Start date
  • #1
dekoi
Question:

lim(x->0) for (tanx - sinx) / (sinx)^2

This is what I got:

= (sinx-sinxcosx) / (cosx)(sinx)^2
= (sinx)(1-cosx) / (sinx)(sinx)(cosx)
= (1 - cosx) / (sinx)(cosx)

However, I can't figure out what to do from this step, as the limit still equals 0/0 at this stage.
 

Answers and Replies

  • #2
mezarashi
Homework Helper
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Why are we posting twice -_-
 
  • #3
dekoi
More people in this forum....
 
  • #5
CarlB
Science Advisor
Homework Helper
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You might see if you can use this handy trig fact:

[tex] (1 + \cos(x))(1-\cos(x)) = 1-\cos^2(x) = \sin^2(x)[/tex]

Carl
 

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