# Limits of function

1. Jan 15, 2008

### dakongyi

1. The problem statement, all variables and given/known data
how to show $$\lim_{n \to \infty}\frac{\sum_{v=0}^{k}(-1)^v{k \choose v}e^{\sqrt{n-v}}}{2^{-k}n^{-\frac{1}{2}k}e^{\sqrt{n}}}=1$$, where $$n \geq k$$

2. Relevant equations
NIL

3. The attempt at a solution
I have absolutely no idea how to start.

2. Jan 16, 2008

### morphism

I'm guessing you have some typos up there. E.g. try it with k=1 - the limit isn't going to be 1.