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Limits of function

  1. Jan 15, 2008 #1
    1. The problem statement, all variables and given/known data
    how to show [tex]\lim_{n \to \infty}\frac{\sum_{v=0}^{k}(-1)^v{k \choose v}e^{\sqrt{n-v}}}{2^{-k}n^{-\frac{1}{2}k}e^{\sqrt{n}}}=1[/tex], where [tex]n \geq k[/tex]

    2. Relevant equations

    3. The attempt at a solution
    I have absolutely no idea how to start.
  2. jcsd
  3. Jan 16, 2008 #2


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    Science Advisor
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    I'm guessing you have some typos up there. E.g. try it with k=1 - the limit isn't going to be 1.
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