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Limits problem help

  1. Apr 2, 2008 #1
    1. The problem statement, all variables and given/known data

    lim as x->infinity [tex]\frac{5x^3-3x^2+8}{ 2x^3 + 9}[/tex]

    2. Relevant equations

    3. The attempt at a solution

    I was told you can look at this highest exponent for the num and dem to find the limit, but I'm not sure what that means. In this case would it be 5/2 because the Xs cancel out?
  2. jcsd
  3. Apr 2, 2008 #2


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    Divide top and bottom by x^3. As x->infinity terms like -3/x go to zero. Get rid of them. So yes, you are left with 5/2.
  4. Apr 2, 2008 #3
    Ok thanks. It makes sense now.
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