lim x->0 (tan 3(x+h)-tan(3x))/h
i hv no clue where to start =(
err.. tan (3h)/h?
simply plugging in 0 for x..
edit: are you sure x is approaching 0?
initially, I thought it's h..
then the answer would have been 3+3tan(3x)^2
and you had to do some mess with identites..
Did you mean lim h->0??
sry, yes i mean lim h->0
Look up a formula for tan(A+B) and apply it to tan(3x+3h). Then simplify, take your limit and use some trig.
It is actually very simple.. don't even need to any trig after simplifying tan(3x+3h) ..
should factor out things.. and they would cancel out nicely.
And, one more thing tan(x)/x = 1 .. (which is simple to prove is you know sin(x)/x =1 as x-->0)
Yep. You don't have to use any trig. But using sec^2(A)=1+tan^2(A) would put it in the simpler form listed in books.
kk thanks i got it =)
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