Limits: showing your working.

  • Thread starter nokia8650
  • Start date
  • #1
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eg. y = 5ke^(-0.2t) - 5k + 2

How would one show the working to show what happens as t tends to infinity? Would something like this be ok?

as t--> infinity

e^(-0.2t) --> 0

therefore 5ke^(-0.2t) ---> 0

therefore 5ke^(-0.2t) - 5k + 2 --> 5k + 2

therefore y ---> 5k + 2

Thanks
 

Answers and Replies

  • #2
Defennder
Homework Helper
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Looks ok. But you left out a minus sign.
 
  • #3
tiny-tim
Science Advisor
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How would one show the working …

Hi nokia8650! :smile:

I guess it means a delta-epsilon proof. :smile:
 
  • #4
HallsofIvy
Science Advisor
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No, I would not say that "show the working" means a "delta- epsilon" proof. What You have done is correct. You might add something like "Since f(x)= ex increases without bound as x increases, e^(-0.2t) --> 0 as t --> infinity".
 

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