- #1
Alexstre
- 19
- 0
Hello!
I'm trying to find the following limit:
[tex]{\lim_{x \to 5}}\ {5-x \over {3-\sqrt{x^2 -16}}[/tex]
I tried 2 things
Simplifying the bottom:
[tex]3-\sqrt{x^2-16}[/tex] = [tex]3-\sqrt{x^2-4^2}[/tex] = 3-x-4 = -1-x
But that doesn't help with what's on top...
I also tried multiplying top and bottom by:
[tex]3+\sqrt{x^2-16}[/tex] but I still ended up with 0/non-zero.
Could anyone point me into the right direction, or correct me if one of those 2 steps was right?
Thanks!
I'm trying to find the following limit:
[tex]{\lim_{x \to 5}}\ {5-x \over {3-\sqrt{x^2 -16}}[/tex]
I tried 2 things
Simplifying the bottom:
[tex]3-\sqrt{x^2-16}[/tex] = [tex]3-\sqrt{x^2-4^2}[/tex] = 3-x-4 = -1-x
But that doesn't help with what's on top...
I also tried multiplying top and bottom by:
[tex]3+\sqrt{x^2-16}[/tex] but I still ended up with 0/non-zero.
Could anyone point me into the right direction, or correct me if one of those 2 steps was right?
Thanks!