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I'm trying to find the following limit:

[tex]{\lim_{x \to 5}}\ {5-x \over {3-\sqrt{x^2 -16}}[/tex]

I tried 2 things

Simplifying the bottom:

[tex]3-\sqrt{x^2-16}[/tex] = [tex]3-\sqrt{x^2-4^2}[/tex] = 3-x-4 = -1-x

But that doesn't help with what's on top...

I also tried multiplying top and bottom by:

[tex]3+\sqrt{x^2-16}[/tex] but I still ended up with 0/non-zero.

Could anyone point me into the right direction, or correct me if one of those 2 steps was right?

Thanks!

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# Homework Help: Limits: Zero / Non-Zero

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