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Line integral of vector field

  1. Jul 29, 2008 #1
    1. The problem statement, all variables and given/known data
    A 160-lb man carries a 25-lb can of paint up a helical staircase that encircles a silo witha radius of 20 ft. If the silo is 90 ft high and the man makes exactly three complete revolutions, how much work is done by the man against gravity in climbing to the top?

    2. Relevant equations
    W= line integral of dot product of F(r(t)) -dot- r'(t)

    3. The attempt at a solution
    My r(t)= (20cost, 20sint, 90)
    r'(t)=(-20sint, 20cost, 0)
    t is between 0 and 6pi
    I know that gravity is -9.8 in the k direction. However I don't know what to use for my vector field....or if I should be using a different r(t). At first I tried using <0,0,-9.8> -dot- <-20sint,20cost,0> but obviously that just gives me zero.
  2. jcsd
  3. Jul 29, 2008 #2


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    The path taken is that described of a helix. How would you parametrise a helix? It should have non-zero components for all the i,j,k directions.
  4. Jul 29, 2008 #3


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    Gold Member

    It's a conservative force so the answer is simply mgh.
    You may take the total displacement vector dotted with minus the force of gravity and you get of course mgh.

    Do you have to prove it with an integral? I don't understand your r(t), the third compoenent (the 90) is not a constant as the man is climbing.
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