Line Integral

  • Thread starter SelHype
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  • #1
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Homework Statement


Let C be the arc of y=x2 from (0,0) to (1,1). Evaluate [tex]\int[/tex]xdx


Homework Equations


C1:
x=t
y=t2
-1 [tex]\leq[/tex] t [tex]\leq[/tex] 1 so -1 [tex]\leq[/tex] x [tex]\leq[/tex] 1

The Attempt at a Solution



dx is x' dt, right?

For some reason, I just can't figure this out. Any help?
 
Last edited:

Answers and Replies

  • #2
gabbagabbahey
Homework Helper
Gold Member
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6
ummm [tex]\int x dx[/tex] is not even a line integral; it's just an ordinary integral....do you mean [tex]\int_{\mathcal{P}} \vec{x} \cdot \vec{ds}[/tex]?
 
  • #3
10
0
No, that is what he has down...Except the C is where the p is on yours. I did not know how to do that. I figured it out, though.

since dx=xdt and x=t,

[tex]\int[/tex] from 0 to 1 of t2dt is 1/3.
 

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