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Line integral

  1. Dec 8, 2013 #1
    LRO8ziP.png

    (disregard the [5+5+5] in the question)


    attempt:
    dr=(et(cost)+(sint)et)[itex]\hat{i}[/itex] + (-et(sint)+(cost)et)[itex]\hat{j}[/itex]

    ∫<3+2xy, x2-3y2>[itex]\cdot[/itex]<et(cost)+(sint)et, -et(sint)+(cost)et>dt

    ..at which point i remembered i had to parametrize F in terms of t, but didn't know how to do
     
  2. jcsd
  3. Dec 8, 2013 #2

    Simon Bridge

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    you want to integrate only over those values of x and y that lie on the curve mapped out by r(t) ... so what determines if a point (x,y) is on r?
     
  4. Dec 8, 2013 #3
    to answer your question, it would be if curve C lies if the domain of F, i don't see how this would help me though, i'm trying to put the vector field in terms of t.
     
  5. Dec 8, 2013 #4
    i would have to put the curve that is in terms of t, into some function of x and y then, how?
     
  6. Dec 8, 2013 #5
    this was a stupid question. Sorry, i just figured it out...
     
  7. Dec 8, 2013 #6

    Simon Bridge

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    Well done :)
     
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