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Line Interseting plane in 3-D

  1. Sep 15, 2009 #1
    1. The problem statement, all variables and given/known data
    Find the point P where the line x = 1 + t, y = 2t, z = -3t intersects the plane x + y - z = -1


    2. Relevant equations



    3. The attempt at a solution
    vector of line= <1,2,-3>

    Am I suppose to find the projection of the two vectors?
     
  2. jcsd
  3. Sep 15, 2009 #2
    Don't you need to find the values of t for which x+y-z=-1?

    Plug x,y and z into the planes equation in terms of t, find the value of t for which the equality holds then transfer it back to the line to find the position of the intersection.
     
  4. Sep 15, 2009 #3
    plug -1 into the line equation right? and that should give me the value of t?
     
  5. Sep 15, 2009 #4
    I havn't done this for a while, but it looks like x+y-z=-1 means that (1+t) + 2t - (-3t) = -1 should give you t, and then you can work out the co-ordinates of this point.
     
  6. Sep 15, 2009 #5
    thanks I figured it out. intersects at point (2/3, -2/3, 1)
     
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