Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Calculus and Beyond Homework Help
Linear Algebra: Augmented matrix echelon form y-space?
Reply to thread
Message
[QUOTE="HallsofIvy, post: 4652730, member: 637751"] Setting the augmented matrix to 2 3 | 1 0 4 1 | 0 1 and completely row-reducing to get 1 0 | -1/10 3/10 0 1 | 2/5 -1/5 give the [b]inverse[/b] matrix to the original matrix. Multiplying that inverse matrix by the (y1, y2) will then give the solution to the original matrix. If you had only the one problem with given values for y1 and y2, row reducing directly with y1, y2 would be simpler. But it often happens in applications that you have an equation like Ax= y with the same "A" but many different "y". In that case it would be simpler to find the inverse to A first, the multiply it by the various y. More likely, your teacher is using this as a way to introduce the "inverse" matrix. [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Calculus and Beyond Homework Help
Linear Algebra: Augmented matrix echelon form y-space?
Back
Top