1. The problem statement, all variables and given/known data Find a number for k in which the system yields no unique solution. [tex]x+y+kz = 3[/tex] [tex]x+ky+z = 2[/tex] [tex]kx+y+z= 1[/tex] 3. The attempt at a solution I know that I need to find a number so that there is no solution and so that there is an infinite number of solutions, I just am not sure how to go about it. I have tried setting it up in row echelon form and here is what I got. [tex]x+y+kz = 3[/tex] [tex](k-1)y - (k-1)z = -1[/tex] [tex]kx+y+z=1[/tex] So I only changed the middle one and I know that if k = 1 then the system will yield no solutions, so there is one number. But I looked in the back and there was another answer. I don't know how to get the other one, and is that even right so far?