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Linear Algebra - Polar decomposition

  1. Apr 6, 2010 #1

    First i calculated the eigenvalues: I got
    [tex](i-\lambda)(-i-\lambda)+1[/tex], so

    Is it correct to go on on like this:


    After calculating a and b, we plug it into f(x) = ax+b -->

    [tex]f(A^{*}A)=\sqrt{A^{*}A}=|A|[/tex] and

    This way i find U, and i think |A|=P

    So i have the polar decompostion A = UP?!
    Is the way correct?


    Edit: A* - Transpose
    Last edited: Apr 6, 2010
  2. jcsd
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