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Linear Algebra Question

  • Thread starter jcharky
  • Start date
  • #1
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The solution of the system

ax + ay - z = 1
x - ay - az = -1
ax - y + az = 1

is (x,y,z) = (a,b,a). If a is not an integer, what is the numberical value of a + b.

So I guess i should plug in (a,b,a) for (x,y,z) first..

a^2 + ab - a = 1
a - ab + a^2 = -1
a^2 - b - a^2 = 1

I am not sure how to solve for a + b though and I am not sure how part that a is not an integer comes into play can someone help?
 

Answers and Replies

  • #2
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  • #3
tiny-tim
Science Advisor
Homework Helper
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Welcome to PF!

Hi jcharky ! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

Your second and third equations have a2 the wrong way round. :redface:
 

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