- #1

jcharky

- 1

- 0

ax + ay - z = 1

x - ay - az = -1

ax - y + az = 1

is (x,y,z) = (a,b,a). If a is not an integer, what is the numberical value of a + b.

So I guess i should plug in (a,b,a) for (x,y,z) first..

a^2 + ab - a = 1

a - ab + a^2 = -1

a^2 - b - a^2 = 1

I am not sure how to solve for a + b though and I am not sure how part that a is not an integer comes into play can someone help?