1. The problem statement, all variables and given/known data Let A and B be square matrices, with B invertible. Show that det(BAB^-1) = det(A) 2. Relevant equations I think its based off the theorem: If A and B are nxn matrices, then det(AB)= det(A)det(B) 3. The attempt at a solution I started by simplifying BAB^-1det(A) to just try to get det(A) but I'm just not sure how to do the proof.