Let U be a subspace of Rn(adsbygoogle = window.adsbygoogle || []).push({});

If aX is in U, where a is non zero number and X is in Rn, show that X is in U

THis seems so obvious... but i m not sure how to show this by a proof

aX is in U and aX is in Rn for sure and U is a subspace of Rn.

Is it true that if U is closed under scalar multiplication then X is in U ?

Please advise!

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# Linear Algebra

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