# Linear Algebra

1. Jan 11, 2010

### EV33

1. The problem statement, all variables and given/known data
Determine all possibilities for the solution set (from among infinitely many solutions, a unique solution, or no solution) of the system of linear equations.

A system of 4 equations in 3 unknowns

2. Relevant equations
None.

3. The attempt at a solution
This is more of a word problem.

Under the assumption that "4 equations in 3 unknown's means a 4X3 Matrix then I would say that there are an infinite amound of solutions because 4X3 matrix could be filled with an infinite amount of options.

Is that correct?

2. Jan 11, 2010

### rock.freak667

With n unknowns you need at least n equations to get a unique solution.

3. Jan 11, 2010

### Dick

If the first equation is a=0 and the second equation is a=1, I doubt there are an infinite number of solutions. Just saying "a 4x3 matrix could be filled with an infinite number of options" means you are thinking about this really vaguely. Try and be more concrete. Any of those options is actually possible. Try and give an example of each.

4. Jan 11, 2010

### Dick

"4" equations. "3" unknowns. There are plenty of equations.

5. Jan 11, 2010

### jegues

Not necessairly, you didn't specify whether you were looking at the augmented matrix or the coefficient matrix. Consider the rank of the matrix(either augmented or coefficient), this should help you determine the number of parameters(free variables) and point you towards a conclusion.

6. Jan 11, 2010

### rock.freak667

well that was my point. Though I probably worded it badly.

7. Jan 12, 2010

### Altabeh

This is an overdetermind system of linear equations which if it happens to have a solution, it is unique. Otherwise it won't have any exact solution assuming no two eauations coincide. You can use methods like "square least" to get the nearest set of solutions that is not always guaranteed to be a good approximation, but still a very useful and reliable one.

AB