- #1

- 75

- 0

I know that u and v are parellel if their dot product is 1.

so if |u dot v| = 1 , fair enough, but how can I show that ||u|| ||v|| will also be equal to 1

any help would be greatly appreciated, thanks in advance :)

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- Thread starter dangish
- Start date

- #1

- 75

- 0

I know that u and v are parellel if their dot product is 1.

so if |u dot v| = 1 , fair enough, but how can I show that ||u|| ||v|| will also be equal to 1

any help would be greatly appreciated, thanks in advance :)

- #2

- 532

- 5

Do you know the definition of the dot product?

- #3

- 22,089

- 3,296

I know that u and v are parellel if their dot product is 1.

This is not true. You must have misunderstood something...

How did you define the dot product?

- #4

- 75

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Not really.. it's just the product of two vectors isn't it?

- #5

- 532

- 5

No, check out the proper definition and then look at your problem again, it should become very clear

- #6

- 75

- 0

Could you perhaps tell me your definiton of the dot product? :D

- #7

Mark44

Mentor

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This is so vague as to be meaningless.Not really.. it's just the product of two vectors isn't it?

You tell us, please.Could you perhaps tell me your definiton of the dot product? :D

- #8

- 532

- 5

a theorem. I'm just so used to seeing it called a definition.

Read this page:

http://tutorial.math.lamar.edu/Classes/CalcII/DotProduct.aspx

and you should be able to answer this question.

- #9

- 75

- 0

This is so vague as to be meaningless.

sorry champ

- #10

Mark44

Mentor

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a

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